(A-B)U(B-A) IN SETS.
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Let A={a,b,c} & B={a,b,d}
LHS=> A-B={c} and B-A={d}
Thus, (A-B) U (B-A)={c,d}
RHS=> A U B= {a,b,c,d}
A ∩ B = {c,d}
Thus, (A U B) - (A ∩ B) = {c,d}
LHS=RHS
Hope it helps.
LHS=> A-B={c} and B-A={d}
Thus, (A-B) U (B-A)={c,d}
RHS=> A U B= {a,b,c,d}
A ∩ B = {c,d}
Thus, (A U B) - (A ∩ B) = {c,d}
LHS=RHS
Hope it helps.
Answered by
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Hi i hope it helps you
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