Math, asked by poonamkulkriti2004, 9 months ago

a + b whole square minus a minus b whole square​

Answers

Answered by apm43
1

Answer:

 ({a + b})^{2}  - (a - b) {}^{2}  \\  {a}^{2}  +  {b}^{2}  + 2ab - (a {}^{2}  +  {b}^{2}  - 2ab) \\  {a}^{2}  +  {b}^{2}  + 2ab -  {a}^{2}  -  {b}^{2}  + 2ab \\  + 4ab

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Answered by ItzAditt007
1

\huge{\mathcal{\blue{\underline{\underline{\pink{HeYa!!!}}}}}}

{\huge{\purple{\mathbb{\bold{ANSWER}}}}}

{\large{\blue{\bold{\underline{IDs\:Used:-}}}}}

▪︎ (x+y)² = x²+y²+2xy.--(1)

▪︎ (x-y)² = x²+y²-2xy. --(2)

{\large{\blue{\bold{\underline{To\:Find:-}}}}}

=》 (a+b)²-(a-b)².

= (a²+b²+2ab)-(a²+b²-2ab).

{From IDs (1) and (2)}

= a²+b²+2ab-a²-b²+2ab

{By opening brackets}

{\large{\red{\boxed{\bold{=\:4ab.}}}}}

Hope this will help you if it HELPS then plz mark my answer as BRAINLIEST.

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