(a/b)^x-1=(b/a)^x-3 find x
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Step-by-step explanation:
(a/b)ˣ⁻¹ = (b/a)ˣ⁻³
=> (a/b)ˣ⁻¹ = [(a/b)⁻¹]ˣ⁻³ (∵ a⁻ⁿ = 1/aⁿ)
=> (a/b)ˣ⁻¹ = (a/b)⁻ˣ⁺³ (∵ (xᵃ)ᵇ = xᵃᵇ)
//When bases are same, powers are equal.
x - 1 = = -x + 3
2x = 4
x = 2
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