Math, asked by vedashreekota2005, 10 months ago

(a/b)^x-1=(b/a)^x-3 find x​

Answers

Answered by spiderman2019
0

Answer:

Step-by-step explanation:

(a/b)ˣ⁻¹ = (b/a)ˣ⁻³

=> (a/b)ˣ⁻¹ = [(a/b)⁻¹]ˣ⁻³   (∵ a⁻ⁿ = 1/aⁿ)

=> (a/b)ˣ⁻¹ = (a/b)⁻ˣ⁺³      (∵ (xᵃ)ᵇ = xᵃᵇ)

//When bases are same, powers are equal.

x - 1 = = -x + 3

2x = 4

x = 2

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