Question

(a-b) x^2 - 6(a+b)x-9(a-b)=0 are real and unequal

Answer 1

Step-by-step explanation: D=36(a+b)^2+36(a-b)^2=36a^2+72ab+36b^2+36a^2-72ab+36b^2=72(a^2+b^2)

x1=(6(a+b)-sqrt(72(a^2+b^2)))/2(a-b)=(3(a+b)-3sqrt(2(a^2+b^2)))/a-b

x2=(3(a+b)+3sqrt(2(a^2+b^2)))/a-b