Question

(a-b)x^2+8(a^2-b^2)+16(a-b)^2=0​

Answer 1

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________________

(a-b)x² = ax²-bx²

8(a²-b²) = 8a²-8b²

16(a-b)² = 16(a²+b²-2ab)

(a-b)x²+8(a²-b²)+16(a-b)² = 0

ax²-bx²+8a²-8b²+16a²+16b²-32ab = 0

x²(a-b) + 24a²+8b²-32ab = 0

x² = (-24a²-8b²+32ab)/(a-b)

x² = -8(3a²+b²-4ab)/(a-b)

x = √[-8(3a²+b²-4ab)/(a-b)]

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Answer 2

Answer:

$\huge{\mathbb{\red {Answer }}}$❤

________________

(a-b)x² = ax²-bx²

8(a²-b²) = 8a²-8b²

16(a-b)² = 16(a²+b²-2ab)

(a-b)x²+8(a²-b²)+16(a-b)² = 0

ax²-bx²+8a²-8b²+16a²+16b²-32ab = 0

x²(a-b) + 24a²+8b²-32ab = 0

x² = (-24a²-8b²+32ab)/(a-b)

x² = -8(3a²+b²-4ab)/(a-b)

x = √[-8(3a²+b²-4ab)/(a-b)]