(a + b) * x ^ 2 + (a + 2b + c) * x + (b + c) = 0 with only factorization not quadratic formula
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Clearly we see that x=1 satisfies the equation
⇒x=1 is a root of the that equation
Let α be other root
Product of roots =1×α=
a+b−2c
a−2b+c
other root =α=
a+b−2c
a−2b+c
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