Question

(a+b)x + (a-b)y = 2ab and (a+b) x -(a-b)y=ab by elimination method

Answer 1

Let (a+b)x+(a-b)y=2ab   ----------------(1)
and(a+b)x-(a-b)y=ab      ----------------(2)

Adding (1)and(2), we get
2(a+b)x=3ab
          x=$\frac{3ab}{2(a+b)}$
same way, subtracting (1)and (2), we get 
2(a-b)y=ab
         y=$\frac{ab}{2(a-b)}$ 

Answer 2

Answer:

Let (a+b)x+(a-b)y=2ab ----------------(1)

and(a+b)x-(a-b)y=ab ----------------(2)

Adding (1)and(2), we get

2(a+b)x=3ab

x=\frac{3ab}{2(a+b)}

2(a+b)

3ab

same way, subtracting (1)and (2), we get

2(a-b)y=ab

y=\frac{ab}{2(a-b)}

2(a−b)

ab