(a+b)x + (a-b)y = 2ab and (a+b) x -(a-b)y=ab by elimination method
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Let (a+b)x+(a-b)y=2ab ----------------(1)
and(a+b)x-(a-b)y=ab ----------------(2)
Adding (1)and(2), we get
2(a+b)x=3ab
x=
same way, subtracting (1)and (2), we get
2(a-b)y=ab
y=
and(a+b)x-(a-b)y=ab ----------------(2)
Adding (1)and(2), we get
2(a+b)x=3ab
x=
same way, subtracting (1)and (2), we get
2(a-b)y=ab
y=
Answered by
1
Answer:
Let (a+b)x+(a-b)y=2ab ----------------(1)
and(a+b)x-(a-b)y=ab ----------------(2)
Adding (1)and(2), we get
2(a+b)x=3ab
x=\frac{3ab}{2(a+b)}
2(a+b)
3ab
same way, subtracting (1)and (2), we get
2(a-b)y=ab
y=\frac{ab}{2(a-b)}
2(a−b)
ab
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