(a-b)x+(a+b)y=a^2-2ab+b^2 and (a+b)(x+y)=a^2+b^2
sove the above by cross multiplication method
fast please i will mark as brainliest :)
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(a+b)x+ (a+b)y = (a+b)(x+y)= (a+b)²
Also, (a+b)(x+y)=a²+b²
This shows that 2ab=0 and thus ab=0
Either a=0 or b=0
Let's assume b=0
Sorry, I did not see the question correctly.
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