(a-b)x+(a+b)y=a²-2ab-b², (a+b)(x+y)=a+b
solve this by elimination method
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a²+b²+2ab is equal to (a+b)²
So (a+b)²/(a+b)
Also it can be written as (a+b)(a+b)/(a+b)
One (a+b) in numerator is cancelled by (a+b) in denominator
So only (a+b) is left in numerator
Ans is (a+b)
Answered by
1
Answer:
Step-by-step explanation:
(a + b) x + (a + b) y = a² + b²... (2)
Subtracting equation (2) from (1), we obtain
(a - b) x (a + b) x = (a² - 2ab-b²) - -
(a² + b²)
(a - b - a - b) x = - 2ab - 2b² - 2bx = -2b (a + b)
x = a + b
Using equation (1), we obtain
(a - b) (a + b) + (a + b) y = a2 - 2ab-b²
a²-b²+ (a + b) y = a² - 2ab-b²
(a + b) y = -2
'y = (-2ab)/(a+b)
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