(a+b)x + (a-b)y = a²+b²
(a-b)x + (a+b)y = a+b²
Solve by elumination method
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Step-by-step explanation:
(a+b)b + (a-b)y = a^2+b^2
here multiply x with (a+b) and y with (a-b)
you will get ax+bx and ay-by = a^2+b^2
now ax+bx+ay-by = a^2+ b^2 (eq 1)
next (a-b)x + (a+b)y = a+b^2
here also multiply x with (a-b) and y with (a+b)
you will get ax-bx and ay+by = a+b^2
now ax-bx + ay+by = a+b^2 (eq 2)
subtract eq1 anf eq2
ax+bx+ay-by=a^2+b^2
ax-bx+ay+by=a+b^2
2ax-2ay=2a^2+2b^2 ( +bx-bx cancel and -by+by cancel elemination method )
2ax-2ay=2a^2+2b^2 (lets take 2 as common)
2(ax-ay)=2(a^2+b^2) [2 on LHS nd 2 on RHS gets cancelled ]
ax-ay=a^2+b^2 this is the answer
hope this helps you
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