Math, asked by justin7720, 4 months ago

(a-b)x²-(3a-b)x+2a=0 by determinent

Answers

Answered by nehagautam1995
0

Answer:

ax²-bx²-3ax-bx+2a=0

a(x²-3x+2)-bx(x-1) = 0

(a-bx)(x²-3x+2)(x-1)=0

Answered by varnikajain12
0

I know it dude

i came here as i am lazy so that o could copy

you also fo the same from google

the method above is different from the one you want so don't copy that otherwise you will have 0 in test

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