(a-b)x²-(3a-b)x+2a=0 by determinent
Answers
Answered by
0
Answer:
ax²-bx²-3ax-bx+2a=0
a(x²-3x+2)-bx(x-1) = 0
(a-bx)(x²-3x+2)(x-1)=0
Answered by
0
I know it dude
i came here as i am lazy so that o could copy
you also fo the same from google
the method above is different from the one you want so don't copy that otherwise you will have 0 in test
Similar questions