Question

(a+b)x2 + 8(a2-b2) x - 20(a-b)2 = 0.​

Answer 1

Answer:

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Step-by-step explanation:

Evaluate an expression :

2.1 Factoring: a2-b2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : a2 is the square of a1

Check : b2 is the square of b1

Factorization is : (a + b) • (a - b)

Equation at the end of step 2 :

((((a+b)2)•(x2))+(8•(a+b)•(a-b)•x))+16•(a-b)2 = 0

Step 3 :

Equation at the end of step 3 :

((((a+b)2)•(x2))+8x•(a+b)•(a-b))+16•(a-b)2 = 0

Step 4 :

Equation at the end of step 4 :

((a+b)2•x2+8x•(a+b)•(a-b))+16•(a-b)2 = 0

Step 5 :

5.1 Evaluate : (a-b)2 = a2-2ab+b2

Equation at the end of step 5 :

a2x2 + 8a2x + 16a2 + 2abx2 - 32ab + b2x2 - 8b2x + 16b2 = 0

Step 6 :

Solving a Single Variable Equation :

6.1 Solve a2x2+8a2x+16a2+2abx2-32ab+b2x2-8b2x+16b2 = 0