(a+b)x² +(a+2b+c)x+(b+c)=0
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Answered by
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Step-by-step explanation:
(a+b-2c)X^2 + (a+b-2c)X +(a+c-2b) X + (a+c-2b) = 0
( a+b-2c)X { X+1} + (a+c-2b) {X+1} =0
(X+1) { (a+b-2c)X + ( a+c-2b)} =0
X = -1 or
(a+b-2c)X = -(a+b-2c)
=> X = -(a+c-2b)/(a+b-2c)
Answered by
1
The value of X is 
Step-by-step explanation:
comparing the value.
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