Question

(a+b)x² +(a+2b+c)x+(b+c)=0

Answer 1

Step-by-step explanation:

(a+b-2c)X^2 + (a+b-2c)X +(a+c-2b) X + (a+c-2b) = 0

( a+b-2c)X { X+1} + (a+c-2b) {X+1} =0

(X+1) { (a+b-2c)X + ( a+c-2b)} =0

X = -1 or

(a+b-2c)X = -(a+b-2c)

=> X = -(a+c-2b)/(a+b-2c)

Answer 2

The value of X is $\frac{-(b+c)}{(a+b)} \ or \ -1$

Step-by-step explanation:

$(a+b)x^2 +(a+2b+c)x+(b+c)=0$

$ax^2+bx+c=0$ comparing the value.

$a=(a+b)$

$b=(a+2b+c)$

$c=(b+c)$

$formula: \frac{-b\pm \sqrt{b^2-4\cdot a \cdot c}}{2\cdot a}$

$x= \frac{-(a+2b+c)\pm \sqrt{(a+2b+c)^2-4\cdot (a+b) \cdot (b+c)}}{2\cdot(a+b)}$

$x= \frac{-(a+2b+c)\pm \sqrt{(a^2+(2b)^2+c^2+2\cdot a\cdot 2b+ 2\cdot 2b\cdot c+2 \cdot c\cdot a-4(ab+ac+b^2+bc)}}{2\cdot(a+b)}$

$x= \frac{-(a+2b+c)\pm \sqrt{(a^2+4b^2+c^2+4\cdot a\cdot b+ 4\cdot b\cdot c+2 \cdot c\cdot a-4ab-4ac-4b^2-4bc)}}{2a+2b}$

$x= \frac{-(a+2b+c)\pm \sqrt{(a^2+c^2 -2\cdot c\cdot a)}}{2a+2b}$

$x= \frac{-(a+2b+c)\pm \sqrt{(a^2+c^2 -2ca)}}{2a+2b}$

$x= \frac{-(a+2b+c)\pm \sqrt{(a-c)^2}}{2a+2b}$

$x= \frac{-(a+2b+c)\pm (a-c)}{2a+2b}$

$x= \frac{-a-2b-c\pm (a-c)}{2a+2b}$

$x= \frac{-a-2b-c+a-c}{2a+2b}\ or \ x= \frac{-a-2b-c-a+c}{2a+2b}$

$x= \frac{-2b-2c}{2a+2b} \ or \ x= \frac{-a-2b-a}{2a+2b}$

$x=\frac{2(-b-c)}{2(a+b)} \ or \ x= \frac{-2(a+b)}{2(a+b)}$

$x=\frac{(-b-c)}{(a+b)} \ or \ x= -1$

$x=\frac{-(b+c)}{(a+b)} \ or \ x= -1$

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