Question

(a - b)x² + ( b - c) x + ( c - a )=0​

Answer 1

ax² - bx² + bx - cx + C - a

= ax² - a - bx² + bx -cx + C

= a ( x² - 1 ) - b ( x² - 1 ) - C ( x - 1 )

= a ( x + 1 ) ( x - 1 ) - b ( x + 1 ) (x - 1 ) - C (x - 1 )

= ( x - 1 ) ( ax + a - bx - b - c)