Question

a, B,Y are zeroes of cubic polynomial
kx3-5x+9
if a3+B3+y3=27 find the
value of K
​

Answer 1

Answer:

k= -1

Step-by-step explanation:

x³+y³+ z³=3 x y z if x+ y+z= 0

since a +b+z=0

therefore ³a +b³+ z ³=3 aby

27= 3×-9/ k

k= -1

this is answer

Answer 2

Answer:

k= -1

Step-by-step explanation:

x³+y³+ z³=3 x y z if x+ y+z= 0

since a +b+z=0

therefore ³a +b³+ z ³=3 aby

27= 3×-9/ k

k= -1