Question

(a) b2 + 7b-8 solve it form ​

Answer 1

Answer:

b is either (-8) or (1)

Step-by-step explanation:

Given---b^2 + 7b - 8=0

(using factorisationbinnthe middle term 7b)

b^2 + 8b - 1b -8=0

(taking (b) common in first two terms and (-1) common in last two terms)

b(b + 8) -1(b + 8)=0 --------(2)

(Finally taking (b+8) common from terms in eq(2) )

(b+8)(b-1)=0

AS THEIR MULTIPLICATION IS 0, EUTHER OF THENTERMS SHOULD BE P. So,

taking b+8=0, we got [b=(-8)]

taking b-1=0, we got [b=(1)]