Physics, asked by goyaljatin8374, 9 months ago

A+B2i+3j+6k and A-B=6i+3j-k find the value of A.B

Answers

Answered by zahaansajid
3

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A + B = 2i + 3j + 6k    ------(1)

A - B = 6i + 3j - k        -------(2)

(1) + (2) =>

2A = 8i + 6j + 5k

A = 4i + 3j + 5/2 k

Substituting this value in (1),

4i + 3j + 5/2 k + B = 2i + 3j + k

B = -2i + 0j - 3/2 k = -2i - 3/2 k

A·B = (4i + 3j + 5/2 k )(-2i + 0j - 3/2 k)

       = -8 + 0 - 15/4

       = -(32 + 15)/4

       = -47/4

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