Question

A baby crawls 8 feet towards west and then 8 feet towards north. It then moves 14 feet towards east. How far and in which direction is the baby from the starting point?

Answer 1

10 feet is the answer

let A be the starting point and E be the final position of the baby. Then,

Answer 2

Answer:

The baby is 10 m away in the North-East direction.

Step-by-step explanation:

• The diagonal distance of the right-angled triangle is measured by the Pythagoras theorem.
• The theorem states that the Square of the diagonal is the sum of the square of the other sides.
• It is given by $H^{2}=P^2+B^2$

Step 1 of 2:

• The diagram of the movement of the baby is drawn step-wise with the notation of the distance and the direction as shown in the figure.
• The distance in the north direction is 8 ft
• The distance in east direction from original point =14-8=6 ft
• The distance of the baby from the starting point is given by the diagonal.
• Diagonal distance is given by  $H^{2}=P^2+B^2$

         $H^2=8^2+6^2\\H^2=64+36\\H^2=100\\h=10$

Step 2 of 2:

• Since the baby is in the quadrant of the north and the east direction.
• The direction is North East.