Question

. A baby is born for every 3 years in a family. If the family has totaly 5 children and some of their ages is 90. Then the age of the eldest child is ? A. 12 Years B. 15 Years C. 18 Years D. 24 Years​

Answer 1

Answer:

Since, the children were born at the interval of three years ,let us assume their age as x, x+3,x+6,x+9,x+12.

given- the sum of five children is 50

therefore,

x+x+3+x+6+x+9+x+12 = 50

5x+30 = 50

5x = 50-30

5x=20

x=4

Hence, age of the youngest child is 4 years.

Answer 2

Answer:

Option D

Step-by-step explanation:

Given:-

A baby is born for every 3 years in a family. The family has totaly 5 children and some of their ages is 90.

To find :-

Find the age of the eldest child is ?

A. 12 Years

B. 15 Years

C. 18 Years

D. 24 Years

Solution :-

Given that

A baby is born for every 3 years in a family.

Let the age of new born baby be X years

The age of remaining babies in the family

= X, X+3 , X+6 , X+ 9 , X+12

The sum of their ages

=> X+X+3+X+6+X+9+X+12

=> (X+X+X+X+X)+(3+6+9+12)

=> 5X+30

According to the given problem

The sum of the ages of 5 children = 90.

=> 5X+30 = 90

=> 5X = 90-30

=> 5X = 60

=> X = 60/5

=> X = 12

The age of new born baby = 12 years

The ages of the remaining babies are

12+3 = 15 years

12+6 = 18 years

12+9 = 21 years

12+12 = 24 years

Answer:-

The age of the eldest child in the family = 24 years

Check :-

Sum of their ages = 12+15+18+21+24 = 90 years and the difference between consecutive two ages is 3 years

Verified the given relations in the given problem