A bad contains rs.155 in the form of 1 rupee, 50 paise, and 10 paise coins in the ratio of 3:5:7. Find the number of each type of coins
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let x be no. of coins
3x*1+5x*0.5+7x*0.10=155
3x+2.5x+0.7x=155
6.2x=155
x=25
so total 1rs coins are 3*25=75
50 paise coins are 5 * 25=125
10 paise coins are 7 *25=175
3x*1+5x*0.5+7x*0.10=155
3x+2.5x+0.7x=155
6.2x=155
x=25
so total 1rs coins are 3*25=75
50 paise coins are 5 * 25=125
10 paise coins are 7 *25=175
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