Math, asked by 349796003, 2 months ago

A badminton coach invites players for a practice tournament. Every player shall play exactly 2 games. Each game is between two players. He knows all players well enough to rank them from best to worst where a stronger player would always beat a weaker player. To have a balanced tournament, he wants to minimize the number of players that win both games. How low can he get this number of double winners by careful planning the pairings?

Answers

Answered by amitnrw
1

Given : A badminton coach invites players for a practice tournament. Every player shall play exactly 2 games. Each game is between two players. He knows all players well enough to rank them from best to worst where a stronger player would always beat a weaker player. To have a balanced tournament, he wants to minimize the number of players that win both games.

To Find : How low can he get this number of double winners by careful planning the pairings?

Solution:

Person with Rank 1 is expected to win  both games.  

and last rank will loose both games.

Rest can be planned in such a way that they win 1 and loose 1.

Number of double winners by careful planning the pairings can be as low as 1

Here is one of the way to plan  , let say there are n players invited

Rank      of players playing against    and who  won

                           Winner

1            2                1

2            3               2

3            4               3

__          __           __

___       ___          _

n-1           n             n-1

1               n              1

Here only player  Rank  1 is winning  both games and Rank last is losing both game

Hence Number of double winners by careful planning the pairings can be as low as 1

Learn More:

A badminton coach invites players for a practice tournament.

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