A bag consists of three red 4 blue and 2 black balls and another bag consists of three red and 6 balls 6 black balls a ball is drawn from each of two bags then the probability that the balls are of different colours is
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Choosing a red ball from the first bag=12∗311=12∗311
Choosing a red ball from the second bag=12∗512=12∗512
∴∴ required probability =12(311+512)=12(311+512)
Choosing a red ball from the second bag=12∗512=12∗512
∴∴ required probability =12(311+512)=12(311+512)
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