Question

A bag contai 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn red not red?

Answer 1

Correct Question:

A Bag Contains 3 red balls & 5 black balls. A ball is drawn t random from the bag. What is the probability that the ball drawn is

i) red

ii) Not red

AnswEr:

Number of Red Balls = 3

Number of Black Balls = 5

Total Number of Balls = Total Number of Red Balls + Total Number of Black Balls

$\implies\sf 3 + 5$

$\implies\bold\pink{8}$

$\rule{150}2$

$\dag\:\small\boxed{\sf{Probability\:=\: \dfrac{Number\:of \: Favourable\: Outcomes}{Total\: Number\: of \; Outcomes}}}$

$\small{\underline{\sf{Probability\: of \: Getting\; Red \: Ball}}}-$

$\implies\sf\dfrac{Number\; of \; Red \; Balls}{Total\; Number\; of \; Balls}$

$\implies\boxed{\sf{\dfrac{3}{8}}}$

$\rule{150}2$

$\small{\underline{\sf{Probability\: of \: Not\: Getting\: Red \: Ball}}}-$

$\implies\sf 1 - Probability\: of\: Getting\; Red\; Balls$

$\implies\sf 1 - \dfrac{3}{8}$

$\implies\boxed{\sf{\dfrac{5}{8}}}$

Answer 2

Given

$\bold{ Total \ number \ of \ red \ balls} = 3\\\bold{Total \ number \ of \ black \ balls} = 5\\\implies \bold{Total \ number \ of \ balls} = 3 + 5 = 8$

a) Probability that the ball drawn is red

$= \dfrac{\bold{Total \ number \ of \ red \ balls}}{\bold{Total \ number \ of \ balls}}$

$= \boxed{\boxed{\bold{\dfrac{3}{8} }}}}$

b) Probability that the ball drawn is not red

$= 1 - \dfrac{3}{8}$

$= \dfrac{8-3}{8}$

$= \boxed{\boxed{\bold{\dfrac{5}{8} }}}$