Question

A bag contain 155 rupees in the form of 1 rupees ,50 pasia and 10 pasia coin in the ratio 3:5:7 . Find the total number of coin

Answer 1

Let the common ratio be x

then no. of.....

1 rupee = 3x

50 paisa = 5x

10 paisa = 7x

According to ques.....

》(1 × 3x ) + (50/100 × 5x ) + (10/100 × 7x ) = 155

》 3x + 5x/2 + 7x/10 = 155

》 30x + 25x + 7x = 1550

》 62x = 1550

》 x = 25

NOW TOTAL NO. OF COINS =

= 3 × 25 + 5 × 25 + 7 × 25

= 375

Answer 2

Answer :-

Total money = Rs. 155

Denominations :-

Rs. 1

50 paisa

10 paisa

Ratio of the $\bf{number}$ of coins = 3:5:7

Value of Rs. 1 coins = 1 × 3 = Rs. 3

Value of 50 paisa coins = 50 × 5 = 250 paisa = Rs. 2.5

Value of 10 paisa coins = 10 × 7 = 70 paisa = Rs. 0.7

Total money = sum of the value of the different denominations

=》 155 = 3x + 2.5x + 0.7x

=》 x = 25

Number of coins = 3x + 5x + 7x = $\bf{375}$