Question

a bag contain 18 balls out of which x balls are red if one ball is drawn random from the bag what is the probability that it is the red?? and if two more red balls are put in the bag the probablity a drawing red ball will be 9/8 times the probablity of drawing a red ball in the first case find the value of x ???​

Answer 1

a)Let the number of red balls be 'x'

Therefore,number of red balls=n(A)= 18-x

n(S)=18

Therefore the probability that it is not a red ball=n(A)/n(S)

                                                                              = 18-x/18  

Two Red Balls Are Added

So,

No . of Red Balls = x + 2

Total no .of Balls = 18 + 2 = 20

P(of red Ball) = x + 2 / 20

P given 9 times of P obtained in A

9/8 * x/18 = (x + 2)/20

x / 16 = (x + 2)/20

(x / 16) *  20 = x + 2

5x / 4 = x + 2

5x = 4x + 8

5x - 4x = 8

x = 8

Therefore,

Initial No.Of Red Balls = 8

Hope It helps you

Answer 2

Answer:

the value of  x is  8

Step-by-step explanation:

i cant explain sorry