Question

a bag contain 2 white and 3red balls are selected at random. find the probability of getting 1 white and 1 red ball

Answer 1

1white ball=5/2
1red ball=5/3

Answer 2

The probability of getting 1 white and 1 red ball is 0.6 .

Step-by-step explanation:

We are given that a bag contain 2 white and 3 red balls and 2 balls are selected at random.

We have to find the probability of getting 1 white and 1 red ball.

The formula for selecting an event from total is given by;

                    $^{n} C_r = \frac{n!}{r! \times (n-r)!}$    where, n = Total balls  

                                                             r = selected balls

Firstly, Number of ways of selecting 1 white ball from total of 2 white balls in a bag = $^{2} C_1$

Similarly, Number of ways of selecting 1 red ball from total of 3 red balls in a bag = $^{3} C_1$

Also, Number of ways of selecting 2 balls from total of 5 balls = $^{5} C_2$

So, the probability of getting 1 white and 1 red ball = $\frac{^{2} C_1 \times ^{3} C_1}{^{5} C_2}$

                                                                                    = $\frac{ \frac{2!}{2! \times (2-1)!} \times \frac{3!}{1! \times (3-1)!}}{ \frac{5!}{2! \times (5-2)!}}$

                                                                                    = $\frac{2 \times 3}{10}$ = 0.6

Therefore, required probability is 0.6 .