Question

A bag contain 3 red balls and 5 black balls. a ball is thrown at random from bag. what is the probability that the ball drawn is (1) red. (2) not red?

Answer 1

Answer:

(1) 3/8

(2) 5/8

Step-by-step explanation:

You have 8 balls. 3 of them are red, 5 of them are black.

You could have two views after drawing the ball. It could either be red or black.

There are 8 ways ( 8 balls) of drawing a ball, without colour differentiation.

(1)Let E be the event of drawing red ball.

You have three favourable chances ( 3 red balls) for drawing a red ball.

By definition of probability, probability of E is

P(E) = 3/8

(2) Let I be the event of not drawing red ball. If you do not want to draw red you could only draw black which has five favourable chances.

Therefore,

P(I) = 5/8