Question

A bag contain 3 white 8 red, 2 black and 5 white balls. One ball is drawn at random. What is the probability that the ball drawn is not black?​

Answer 1

Step-by-step explanation:

n(s)=18

n(e)=16

now

p(e). = n(e)/n(s)

=16/18

=8/9

Answer 2

Answer:

$\large \: Probability (not \:black \: ball) = \frac{8}{9}$

Step-by-step explanation:

Given :-

• No. Of White Ball= 3+5=8
• No. Of Red Ball = 8
• No. Of Black = 2
• Total Number Of Balls = 18

$\rule{200} {2}$

Solution :-

Probability of Event = Favorable Outcome / Total Outcome

Not Black Ball= Total Number Of Balls - Black Ball.

Not Black Ball=16

• P(Of Not Black Ball) = 16/18
• Probability (Of Not Black Ball) = 8/9

Thank You.

MAKE IT BRAINLIST ANSWER.......