A bag contain 3red.4black.and 5 green balls of the same size .A ball is drawn is (a) red (b) neither red nor black
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a is 1/4 and b is5/12
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1
total no of balls = 3+4+5 = 12
(a) no of red balls=3
probability of getting red ball = 3/12= 1/4
(b) neither red nor black = 12-(4+3)=12-7=5
probability of getting neither red nor black =5/12
(a) no of red balls=3
probability of getting red ball = 3/12= 1/4
(b) neither red nor black = 12-(4+3)=12-7=5
probability of getting neither red nor black =5/12
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