A bag contain 4 black, 3 red and 9 green balls. One ball is drawn at random. What is the
probability that the ball drawn is:
(a) a green ball?
(b) a non-green ball?
Answers
Answered by
2
Answer:
no. of red balls = 3
no. of black balls = 4
no. of green balls = 9
total no. of balls = 3+4+9 = 16
1. a green ball = 9/16
2. a non green ball = 7/16
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Answered by
10
Answer:
(a) N(s)=4+3+9=16
N(b)=4n(r)=3
N(g)=9
Probability of green ball= n(g) /n(s)
". ". ". ". =9/16
(b) probability of a non-green ball is = n(s)-n(b+r) /n(s)
=7/16
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