Question

a bag contain 4 red ball and 6 green ball and some white ball. if the probability of not drawing a white ball in one draw be 2/3 . then find the number of white ball​

Answer 1

Answer:

Let the number of white balls be n.

Total number of balls = 4+6+n = 10+n

P(drawing red ball) = 4/10+n

P(drawing green ball) = 6/10+n

P(drawing white ball) = n/10+n

P(not drawing white ball) = 2/3 (Given)

P(drawing white ball) = 1-2/3 = 1/3

Therefore, we have:

n/10+n = 1/3

Solve this equation to get the value of n, that is, the number of white balls.