Question

A bag contain 5 red balls 4 yellow balls 3 green balls find the probality of getting (1) green ball and (2) not a yellow ball

Answer 1

Answer:

0

Step-by-step explanation:

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Answer 2

The probability of drawing either a red or a green ball is 7/12.

Step-by-step explanation:

There are 12 possible balls you can draw so the denominator will be 12, there are 4 red balls and 3 green balls, so there are 7 balls that fit the requirement of being either red or green. The probability of drawing either a red or a green ball is 7/12.