Question

A bag contain 50 paisa 25 paisa and 10 paisa coins in tge ratio7:8:3 ammounting to rs 87. Find the number of 10 paisa coins ?

Answer 1

→ Assume bag contain x coin.

So, 50 paise = x coin

25 pasie = 2x coin

20 paise = 4s coin

10 paise = 8x coin

→ total amount in bag = 52 Rs

So, 527 = 5200 paise

→ let,

∴50×x+25×2x+20×4x+10×8x=5200

∴260x=5200

∴x=20 coin

→20paise,

coin for 20 paise =4×x

=4×20

=80

So, the Ans is 80.

Answer 2

Answer:

A bug contain coin 50 paise, 25 paise, 20 paise

& 10 paise in ratio 1:2:4:8 respectively.

→ Assume bag contain x coin.

So, 50 paise = x coin

25 pasie = 2x coin

20 paise = 4s coin

10 paise = 8x coin

→ total amount in bag = 52 Rs

So, 527 = 5200 paise

→ let,

∴50×x+25×2x+20×4x+10×8x=5200

∴260x=5200

∴x=20 coin

→20paise,

coin for 20 paise =4×x

=4×20

=80

So, the Ans is 80.

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