Question

A bag contain 50 paise , 20 paise and 10 paise coins are in the ratio 8 : 15 : 20 . If their total amount is rs. 900 . Find number 10 paise coins is

Answer 1

Answer:

40

Step-by-step explanation:

Given,

20p : 50p : 1rs =7:8:5

So,

20p=7x

50p=8x

1rs=5x

So,

7x+8x+5x=100

20x=100

x=5

Verification,

Amount(rs.)=5(5)*1

                  =25 Rs.

Amount(20p)=7(5)*1/5

                      =7

So,

difference=25-7

                =18

                      which is given.

So,

Number of 50p coins=8(5)

                                   *40*

Answer 2

The number of 10 paise coins is 2000.

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Let's solve the given problem:

The ratio of the number of 50 paise, 20 paise and 10 paise coins are = 8 : 15 : 20

So, let's say,

"8x" → number of 50 paise coins

"15x" → number of 20 paise coins

"20x" → number of 10 paise coins

The total amount in the bag is Rs. 900

Therefore, we can form the equation as,

$(8x \times 0.50) + (15x \times 0.20) + (20x\times 0.10) = 900$

$\implies 4x + 3x + 2x = 900$

$\implies 9x = 900$

$\implies x = 100$

∴ The no. of 10 paise coins = 20x = 20 × 100 = 2000

Thus, the number 10 paise coins in the bag are 2000.

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