a bag contain 5red ball and some blue balls.if the probablability of drawing a blue ball is double that of a red ball determine the number of blue ball in the ba
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total number of balls=5y
probability of blue ball=3×probability of red ball_
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Step-by-step explanation:
Given that:
- A bag contains 5 red balls and some blue balls.
Let us assume:
- A bag contains x blue balls.
- Total number balls in the bag = 5 + x
To Find:
- The number of balls in the bag.
Formula used:
- P(E) = F/T
Where,
- P = Probability
- E = Events
- F = Favourable outcomes
- T = Total outcomes
Now we have,
- Total outcomes = 5 + x
- Favourable outcomes for blue ball = x
- Favourable outcomes for red ball = 5
Given that:
- The probability of drawing a blue ball is double that of a red ball.
P(drawing a blue ball) = 2 × P(drawing a red ball)
⇒ x/(5 + x) = 2 × 5/(5 + x)
Cancelling (5 + x) both sides.
⇒ x = 2 × 5
⇒ x = 10
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