Question

A bag contain 5red balls 16black balls 3 yellow balls find the probability​

Answer 1

Answer:

HOLA

N(S) = 5+16+3 = 8+16= 24

PROBABITY OF RED BALL = 5/ 24

PROBABITY OF YELLOW BALL

= 3/24 = 1/8

PROBABITY OF BLACK BALL = 16/24 = 2/3

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Answer 2

A bag contain 5 red balls, 16 black balls and 3 yellow balls.

therefore, n(S) =24

let A be the event of getting red balls

since we know that there are 5 red balls

therefore n(A) =5

p(A) =n(A) /n(S)

=5/24

Let B be the event of getting black balls.

since we know that there are 16 black balls.

therefore, n(B) =16

p(B) =n(B) /n(S)

=16/24

=2/3

let C be the event of getting yellow balls

since we know that there are 3 yellow balls

therefore n(C) =3

p(C) =n(C) /n(S)

=3/24

=1/8