A bag contain 6 red, 4 white and 8 blue balls. If three balls
are drawn at random, find the probability that:
i. one is red and two are white
ii. two are blue and one is red
iii. one is red
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total balls = 18
red balls=6
white balls=4
blue balls= 8
i) ans =sum of total balls/sum of balls drawn
=18/1red ball + 2 white ball
= 18/3
=6
ii)18/2+1
18/3
6
iii) 18/1 is the answer
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