Question

A bag contain 6 red ball 5 black ball a ball is drawn at a random from the bag what is the probability 1)red ball 2)not red ?​

Answer 1

Answer:

1 6/11

25/11

this the answer

Answer 2

$\Large {\underline {\underline {\text {\maltese \: {\red {Question :-}}}}}}$

A Bag contains 6 Red Balls and 5 Black Balls. A Ball is drawn at random from the Bag. What is the Probability of getting

(i) a Red Ball

(ii) not a Red Ball?

$\Large {\underline {\underline {\text {\maltese \: {\red {Solution :-}}}}}}$

Given,

A Bag contains 6 Red Balls and 5 Black Balls and a Ball is drawn at Random from the Bag.

Then, The Total Number of Balls in the Bag = 6 + 5 = 11 Balls

Total Number of Trials = 11

Probability of getting a Red Ball = $\dfrac{\textbf {No. of Red Balls in the Bag}}{\textbf {Total Number of Trials}}$

Then, Probability of getting a Red Ball = $\bold {\dfrac {6}{11}}$

Similarly,

Probability of getting a Non - Red Ball = $\dfrac{\textbf {No. of Balls other than the Red Ball}}{\textbf {Total Number of Trials}}$

No. of Balls other than the Red Ball = 5 Black Balls + 1 Ball picked at Random = 6 Balls

Then, Probability of getting a Non - Red Ball = $\bold {\dfrac {6}{11}}$