a bag contain 6 red balls,8 white balls,5 green balls and 3 black ball.one ball is drawn at random from the bag .find probability that the ball drawn is; niether white nor black?
Answers
Answered by
3
Answer:
1/2
Step-by-step explanation:
TOTAL OUTCOMES = 6+8+5+3=22
WHITE OR BLACK OUTCOMES= 8 + 3=11
HENCE THE PROBABILITY = 11/22=1/2
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Answered by
2
Answer:
1/2
Step-by-step explanation:
total no of balls = 6+8+5+3=22
no of white n black balls = 8+3 =11
no of balls that r neither white nor black = 22-11=11
probability ( neither white nor black ball )= (no of balls that are neither white nor black) /(total no of balls )
= 11 / 22= 1/2
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