Question

A bag contain 6 red balls and 5 blue balls. one ball is drawn at. random .what is the probability of getting a blue ball ?​

Answer 1

Answer:

ANSWER

No. of red balls =n(R)=6

Let, no. of blue balls be x, n(B)=x

Total no. of balls in bag=n(T)=6+x

We know that, Probability P(Event) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

Probability of drawing a red ball, P(R)=

6+x

n(R)

Probability of drawing a blue ball, P(B)=

6+x

n(B)

Given,

Probability of drawing a blue ball from the bag is twice that of a red ball

i.e., P(B)=2×P(R)

6+x

n(B)

=2×

6+x

n(R)

x=2×6

n(B)=x=12

Total no. of balls in bag=n(T)=6+x=6+12=18.

Answer 2

5/11 is the probability of getting a blue ball.