A bag contain 6 red balls and 5 blue balls. one ball is drawn at. random .what is the probability of getting a blue ball ?
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3
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ANSWER
No. of red balls =n(R)=6
Let, no. of blue balls be x, n(B)=x
Total no. of balls in bag=n(T)=6+x
We know that, Probability P(Event) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
Probability of drawing a red ball, P(R)=
6+x
n(R)
Probability of drawing a blue ball, P(B)=
6+x
n(B)
Given,
Probability of drawing a blue ball from the bag is twice that of a red ball
i.e., P(B)=2×P(R)
6+x
n(B)
=2×
6+x
n(R)
x=2×6
n(B)=x=12
Total no. of balls in bag=n(T)=6+x=6+12=18.
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13
5/11 is the probability of getting a blue ball.
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