Math, asked by anikeshraj660, 9 hours ago

A bag contain ₹ 750 in the form of rupee, 50 p and 25 pcoins in the ratio 5: 8: 4 find the number of coins of each type.​

Answers

Answered by LakshmunNaidu
0

Answer:

Total amount in the bag = Rs 750

Let the number of rupee be 5x, number of 50 paisa coin be 8x and number of 25 paisa coin be 4x

According to the question

5x(1) + 8x(0.5) + 4x(0.25) = 50

5x + 4x + x = 750

10x = 750

x = 75

Therefore,

Number of coin of rupee 5 x 75 = 375

Number of coin of 50 paisa = 8 x 75 = 600

Number of coin of 25 paisa= 4 x 75 = 300

Answered by virenderyadav1476
0

Answer:

300 coins of 25 paise

600 coins of 50 paise

375 coins of 1 ruppee

Step-by-step explanation:

Total amount in bag = 750 rs

Ratio of coins =5:8:4

Let 1 rupee be 5X

Let 50 paise coins be 8X

Let 25 paise coins be 4X .

1 rupee = 100/100 = 1

50 paise = 50/100 = 0.5

25 paise = 25/100 = 0.25

According to this question

5X × 1 + 8X × 0.5 + 4X × 0.25 = 750 rs

5X + 4X + 1X = 750 rs

10X = 750 rs

X = 75 rs

Then

5X = 5×75 = 375 ( 1 ruppee coin )

8X = 8×75 = 600 ( 50 paise coins )

4X = 4×75 = 300 ( 25 paise coins )

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