Question

a bag contain b blue balls and r red balls. if two balls are drawn at random ,then probability of drawing two red balls is five times the probability of drawing two blue balls. the probability of drawing one ballvof each other is six times the probability of drawing two blue balls. then​

Answer 1

Step-by-step explanation:

What is the product of a number of factors of 16 and the largest prime factor is 42?

A. 35

B. 25

C. 30

D. 42

E. 28

Answer 2

Let the number of red and blue balls be r and b , respectively.

Then,the probability of drawing two red balls is

p

1

4

=

r+b

C

2

r

C

2

=

(r+b)(r+b−1)

r(r−1)

The probability of drawing two blue balls is

p

2

=

r+b

C

2

b

C

2

=

(r+b)(r+b−1)

b(b−1)

The probability of drawing one red and one blue ball is

p

3

=

r+b C 2

r C 1 × b C 1 = (r+b)(r+b−1)

=2br

By hypothesis p

1

=5p 2

and p 3

=6p 2

∴r(r−1)=5b(b−1) and 2br=6b(b−1)

⇒r=6,b=3

b+r=9,br=18