A bag contain rs 125 paise and 10 paise coins in the ratio of 6:5:3 amounting to rs 280 coins find the no.of coin of each type
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let the ratio be 6x,5x,3x
6x+5x+3x=280
14x=280
x=20
then coins are
6x=6×20=120
5x=5×20=100
3x=3×20=60
then 280/- =28000 paise
now 125 paise coins=28000/125=224 coins
10 paise coins=28000/10=2800
6x+5x+3x=280
14x=280
x=20
then coins are
6x=6×20=120
5x=5×20=100
3x=3×20=60
then 280/- =28000 paise
now 125 paise coins=28000/125=224 coins
10 paise coins=28000/10=2800
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