Question

a bag contain rupees one kind and rupees to coin those total value is rupees 70 if the number of phase 1 coin is 5 times that of rupees two coins find the number of coins of each type​

Answer 1

Answer:

₹2 coins: 10

₹1 coins: 50

Explanation:

Let's assume total number of ₹2 coins to be "x" then,

Total number of ₹1 coins = 5x

Total amount of ₹1 coins = 5x × ₹1 = ₹5x

Total amount of ₹2 coins = x × ₹2 = ₹2x

Total amount = ₹70

So,

₹5x + ₹2x = ₹70

₹7x = ₹70

x = ₹70/₹7

x = 10

Therefore,

Number of ₹2 coins = 10

Number of ₹1 coins = 5 × 10 = 50

Answer 2

Answer:

QUESTION:-

a bag contain rupees one kind and rupees to coin those total value is rupees 70 if the number of phase 1 coin is 5 times that of rupees two coins find the number of coins of each type

SOLUTION:-

Let the number of ₹2 coins be x.

Then, the number of ₹1 coins = 5x

Total value of ₹2 coins + Total value of ₹1 coins = 70

$(2 \times x) + (1 \times 5x) = 70 \\ 2x + 5x = 70 \\ 7x = 70 \\ x = \frac{70}{7} = 10$

Since x = 10, therefore, 5x = 5 × 10 = 50

Hence , the number of ₹2 coins = 10 and the number of 1 coins = 50

Ans) 2 coins = 10

1 coins = 50