Question

A bag containing 6 white balls numbered from 1 to 6 and 4 red balls numbered from 7 to 10. A ball is drawn at random. Find the probability of getting i. a white ball ii. an even number iii. a white ball and an even number iv. a red ball
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Answer 1

Step-by-step explanation:

Number of white balls =6

Number of red balls =4

Total number of balls =10

Thus, n(S)=10

Let A be event of getting number in even ball.

A={2,4,6,8,10}

n(A)=5

P(A)=

n(S)

n(A)

=

10

5

=

2

1

Let B be event of getting white ball

n(B)=6

P(B)=

n(S)

n(B)

=

10

6

=

5

3

Answer 2

Number of white balls =6

Number of red balls =4

Total number of balls =10

Thus, n(S)=10

Let A be event of getting number in even ball.

A={2,4,6,8,10}

n(A)=5

P(A)=n(S)n(A)=105=21

Let B be event of getting white ball

n(B)=6

P(B)=n(S)n(B)=106=53