Math, asked by nitishshaw80, 1 year ago

A bag containing 8 red and 5 green balls. Two balls are drawn without replacement (simultaneously) from the bag. Find the probability that both the balls drawn are green.

Answers

Answered by Ezekiel9

The probability of green balls will be=5/39

nitishshaw80: thank u so much...

nitishshaw80: and in math what is the meaning of * ?????? u know that??

Ezekiel9: you want **?????? meaning

nitishshaw80: only *

nitishshaw80: only = *

Ezekiel9: It stands for relation between two function like a*b=(a+b)/2 so here * indicates the relation between a and b

nitishshaw80: it means * = +

nitishshaw80: am I right..??

Ezekiel9: It depends on the question.. above was just an example

nitishshaw80: Ooooo

Answered by tardymanchester

Answer:

The probability that both the balls drawn are green $P=\frac{5}{39}$ .

Step-by-step explanation:

Given : A bag containing 8 red and 5 green balls. Two balls are drawn without replacement (simultaneously) from the bag.

To find : The probability that both the balls drawn are green?

Solution :

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

Total number of outcomes = 8+5=13

Probability on first drawn getting green ball is

$P_1=\frac{5}{13}$

Two balls are drawn without replacement (simultaneously) from the bag.

Probability on second drawn getting green ball is

$P_2=\frac{4}{12}$

Therefore, The probability of getting two balls green is

$P=P_1\times P_2$

$P=\frac{5}{13}\times\frac{4}{12}$

$P=\frac{20}{156}$

$P=\frac{5}{39}$

Hence, The probability that both the balls drawn are green $P=\frac{5}{39}$ .

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