A bag containing 8 red and 5 green balls. Two balls are drawn without replacement (simultaneously) from the bag. Find the probability that both the balls drawn are green.
Answers
Answer:
The probability for which both the balls are green is \bold{\frac{5}{39}}395
Solution:
The total balls that are contained in the bag is 8 + 5 = 13, the number of red ball = 8 and the number of green ball = 5.
The possibility of drawing first ball green without replacing =\frac{\text {total number of green ball}}{(\text { total number of balls })-1}=\frac{5}{13}=( total number of balls )−1total number of green ball=135
The possibility of drawing second ball green without replacing = \frac{(\text {total numberof green ball })-1}{(\text { total number of balls })-1}=\frac{4}{12}( total number of balls )−1(total numberof green ball )−1=124
Step-by-step explanation:
Therefore, the ‘probability’ of picking both balls green is P(G)=\frac{5}{13} \times \frac{4}{12}=\frac{5}{39}P(G)=135×124=395
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Answer:
5/13
Step-by-step explanation:
total number of green balls = 5
total number of balls = 8+ 5 = 13
Hence probability = 5/13