Math, asked by anusridasari123, 6 months ago

a bag containis 8red, 6 white and 4black balls. A ball is drawn at random. what is the probability that the drawn ball is neither white or black? ​

Answers

Answered by shritikantg29
0

ANSWER

Total no. of balls in the bag is 18 (8 red, 4 black and 6 white)

Solution(i):

No. of red or white balls in bag is 14 (8 red and 6 white)

Therefore,  

14

C  

1

​  

( Selecting 1 out of 14 items) times out of  

18

C  

1

​  

( Selecting 1 out of 18 items) a red or white ball is picked.

Answered by ap5495989
8

Answer:

ANSWER

Total no. of balls in the bag is 18 (8 red, 4 black and 6 white)

Solution(i):

No. of red or white balls in bag is 14 (8 red and 6 white)

Therefore,

14

C

1

( Selecting 1 out of 14 items) times out of

18

C

1

( Selecting 1 out of 18 items) a red or white ball is picked.

Let E be the event of drawing a red or white ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

18

C

1

14

C

1

=

18

14

=

9

7

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