A bag contains 10 green balls,5 white balls,and 6 black balls.Probability of picking a white ball is *
Answers
Step-by-step explanation:
Let W,B,G be the event of selecting a white, black, green ball respectively.
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)=
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W)
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W)
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) =
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 20
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)=
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B)
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B)
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) =
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 20
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)=
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G)
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G)
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) =
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) = 20
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) = 203
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) = 203
Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) = 203
Answer:
5/21
Step-by-step explanation: there are total 21 balls so probability to taking a white ball is 5/21
i hope it is helpful to you . if it help to clarify your answer then please mark me as brainliest