Question

A bag contains 10 green balls,5 white balls,and 6 black balls.Probability of picking a white ball is *​

Answer 1

Step-by-step explanation:

Let W,B,G be the event of selecting a white, black, green ball respectively.

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)=

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W)

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W)

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) =

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 20

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)=

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B)

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B)

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) =

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 20

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)=

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G)

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G)

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) =

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) = 20

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) = 203

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) = 203

Let W,B,G be the event of selecting a white, black, green ball respectively.n(S)=10+5+3+2=20n(W)=10,n(B)=5,n(G)=3P(W)= n(S)n(W) = 2010 P(B)= n(S)n(B) = 205 P(G)= n(S)n(G) = 203

Answer 2

Answer:

5/21

Step-by-step explanation: there are total 21 balls so probability to taking a white ball is 5/21

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