Question

a bag contains 10 green balls and some red balls if the probability of drawing red ball is three times that the green wall determine the number of red balls in the bag

Answer 1

Answer:

Have a look at this picture::

Answer 2

Answer:

There are 30 red balls in the bag.

Step-by-step explanation:

To find:-

The number of $red$ balls in the bag.

According to the question,

The number of green balls = 10

Let the number of red balls be n.

Then,

The total number of balls in the bag = 10 + n

The $probability$ of drawing the red ball is,

P(Red ball) = (No. of red balls)/(Total no. of balls)

                  = n/(10 + n)

The $probability$ drawing the green ball is,

P(Green ball) = (No. of green balls)/(Total no. of balls)

                  = 10/(10 + n)

Since the probability of drawing red ball is 3 times that the green ball, i.e.,

P(Red ball) = 3 × P(Green ball)

$\frac{n}{10+n}=3\times \frac{10}{10+n}$

n = 3 × 10

n = 30

Therefore, there are 30 red balls in the bag.

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